GAT General Test

 GAT GENERAL TEST Sample 3 Questions Solution(Quantitative) Quick Response Question 350 x 1 = 0 + 350 = 350 233 + 0 = 1 x 233 = 233 20 + ( 25 + 44) = (20 + 25 ) + 44 21 x (9 + 11) = (21 x 9 ) + (21 x 11) 250 x (10 + 1) = (250 x 10) + ( 250 x 1) GCD HCF LCM Answer Q1: The solution of this question can be calculated using both HCF and GCD. GCD Method To find the greatest length of pieces that can be obtained when cutting three strings of lengths 140 cm, 166 cm, and 200 cm into equal-sized pieces without any string left over, we need to find the greatest common divisor (GCD) of these three lengths. To find the greatest length of pieces that can be obtained when cutting three strings of lengths 140 cm, 166 cm, and 200 cm into equal-sized pieces without any string left over, we need to find the greatest common divisor (GCD) of these three lengths. Using the prime factorization method, let's find the GCD: Step 1: Prime factorize the numbers 140, 166, and 200. - 140

Solution of Sample 1 Questions (Quantitative) 1. suppose W= women and M=men so 8(2M+3W) = 1 hence (for 8 days) 2M+3W=1/8 ----- (1) hence 12(4M+5W) = 1 so (for 12 days) 4M+5W=1/12  ----- (2) mutiply eq(1) by 2 4M+6W=1/4 now subtract eq(2) from it    4M + 6W = 1/4    4M + 5W = 1/12 - --------------------------     0   + 1W = 1/4 - 1/12 = (3-1)/12 = 1/12   1W = 1/12 hence 12W = 1 so 12 women can complete a task in a day. 2. Suppose Ali is X years old. And Asif is 30 years old. (Present) three years before Ali was10 years older then Asif so Asif was 30-3=27 years old. (3 year before) Ali was 10 years older than Asif= 10+ 27=37 years old (3 year before) So now Ali is 27+3=40 years old. 3. Answer is c 654*654= 427716 4. X=13 and Y= 10 so X-Y=13-10=3 5. Total time/ number of question=120/100=12/10=6/5=1.2 minutes 6. Average=Sum of all the quantities/No. of quantities so, 75 = Sum of all the quantities/5 and Sum of all the numbers=75*5=375. 7. Percentage=obtaine